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31 October, 06:17

Physical therapists know as you soak tired muscles in a hot tub, the water will cool down as you heat up. If a 67.9 person at 37.1 oC immerses in 50.2 kg of water at 40.5o C, the equilibrium temperature is 38.7 oC. What is the specific heat of the person? Use 4.186 kJ/kgoC for the specific heat of water. Answer to 3 significant figures in kJ/kgoC.

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  1. 31 October, 07:44
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    Q1=Q2

    m1c1 (t-t1) = m2c2 (t2-t)

    67.9kg * c1 * (38.7°C-37.1°C) = 50.2kg * 4186 J/kg°C * (40.5°C-38.7°C)

    67.9kg * c1 * 1.6°C = 50.2kg * 4186 J/kg°C * 1.8°C

    108.64 kg°C * c1 = 378246.96 J

    c1 = 378246.96J / 108.64kg°C

    c1=3481.65 J/kg°C
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