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16 August, 15:33

Calculate the number of Joules given off by 617 grams of water cooling from 65°C to 28°C. [Cw=4.186 J/g*Co]

Q=mC_w/Delta T

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  1. 16 August, 16:19
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    The heat energy lost or gained by a substance is given by the equation

    Q = mCΔT, where

    Q is the heat energy gained or lost by a substance,

    m is mass (in grams),

    C is the specific heat of the substance,

    ΔT is the change in temperature (final temperature - initial temperature).

    The joules given off by 617 grams of water cooling from 65°C to 28°C, given the specific heat of water as Cw=4.186 J/g*Co, is:

    Q = mCwΔT

    Q = (617) (4.186) (28 - 65)

    Q = - 95562.194

    Negative means heat is lost, so 96000 J of heat was lost.
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