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21 April, 09:11

A 2.00 C charge moves from a + 50.0 V equipotential line to a + 40.0 V equipotential line. What is the change in the electric potential energy of the charge field system?

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  1. 21 April, 10:40
    0
    Change in electric potential energy

    = charge x potential difference

    = 2 x (50 - 40)

    = 20 J

    Potential will be decreased by this amount.
  2. 21 April, 12:48
    0
    Potential on first line, V1 = 50 V

    Potential on second line, V2 = 40 V

    Charge, q = 2 C

    Change in potential, ΔV = V1 - V2 = 50 - 40 = 10 V

    Potential energy is given by

    U = q x ΔV

    U = 2 x 10

    U = 20 J
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