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21 December, 18:04

A block and tackle of six pulley is used to raise a load of 300N steadily through a height of 30m, if the workdone against friction is 2000j. Calculate;

1. The workdone by the effort

2. The efficiency of the system

3. The applied effort

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  1. 21 December, 18:31
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    work accomplished = 300*30

    = 9,000 J

    applied work = 9,000 + 2,000 = 11,000 Joules

    efficiency = 100 * work accomplished/work applied

    = (9/11) 100 = 81.8 %

    force applied = (300/6) /.818

    = 61.1 N

    assuming that the 6 in your question refers to mechanical advantage
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