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8 January, 00:24

You have a 9V battery connected to a device you wish to power. 5C of charge flows out of the battery over the course of twohours. What is the average current (in Amps) the flowed during that time?

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Answers (2)
  1. 8 January, 02:09
    0
    Answer: 0.00625A

    Explanation:

    Quantity of charge Q flowing in a circuit per time is equal to the product of the current flowing and time take. Mathematically

    Q = It ... 1

    Where Q is the charge, I is the current and t is the time

    For a charge across a capacitor, Q = CV ... 2

    C is the capacitance of the capacitor

    V is the voltage

    Equating 1 and 2, we have

    It = CV

    I = CV/t

    Given C = 5C, V = 9V and t = 2hrs = 120seconds

    I = 5*9/7200

    I = 45/7200

    I = 0.00625A

    Average current that flowed during that time is 0.00625A
  2. 8 January, 02:56
    0
    0.00625 A.

    Explanation:

    From Faraday's law of electricity,

    Quantity of electric charge = Current * time.

    Q = It ... Equation 1

    Where Q = Quantity of charge, I = current, t = time.

    Making I the subject of the equation,

    I = VQ/t ... Equation 2

    Given: Q = 5 C t = 2 h = (2*3600) s = 7200 s, V = 9 V

    I = 5*9/7200

    I = 0.00625 A

    Hence the average current flowing through = 0.00625 A.
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