Ask Question
24 December, 08:21

A flat screen is located 0.55 m away from a single slit. Light with a wavelength of 544 nm (in vacuum) shines through the slit and produces a diffraction pattern. The width of the central bright fringe on the screen is 0.052 m. What is the width of the slit?

+4
Answers (1)
  1. 24 December, 11:20
    0
    The diffraction pattern is given as

    Sinθ = mλ/ω

    Where m=1,2,3,4 ...

    Now, when m=1

    Sinθ = λ/ω

    Then,

    ω = λ/Sinθ

    The width of the central bright fringe is given as

    y=2Ltanθ. From trigonometric

    Then,

    θ=arctan (y/2L)

    Given that,

    y=0.052m

    L=0.55m

    θ=arctan (0.052/2*0.55)

    θ=arctan (0.0473)

    θ=2.71°

    Substituting this into

    ω = λ/Sinθ

    Since λ=544nm=544*10^-9m

    Then,

    ω = 544*10^-9/Si. 2.71

    ω = 1.15*10^-5m.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A flat screen is located 0.55 m away from a single slit. Light with a wavelength of 544 nm (in vacuum) shines through the slit and produces ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers