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17 July, 05:03

An object weighs 10N in air and 70N in water. What is it's weight when immersed in a liquid of relative density 1.5?

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  1. 17 July, 06:52
    0
    5.5 N

    Explanation:

    We are given;

    Real weight of an object in air as 10 N Apparent weight in water as 7 N Relative density of a liquid is 1.5

    We need to calculate the apparent weight when in liquid.

    First we calculate upthrust

    Upthrust = Real weight - Apparent weight

    = 10 N - 7 N

    = 3 N

    Then calculate the upthrust in the liquid.

    we need to know that;

    Relative density of a liquid = Upthrust in liquid/Upthrust in water

    Therefore;

    1.5 = U : 3 N

    Upthrust in liquid = 3 N * 1.5

    = 4.5 N

    Therefore, the upthrust of the object in the liquid is 4.5 N

    But, Upthrust = Real weight - Apparent weight

    Therefore;

    Apparent weight in Liquid = Real weight - Upthrust

    = 10 N - 4.5 N

    = 5.5 N

    Thus, the weight when the object is immersed in the liquid is 5.5 N
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