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17 July, 04:37

It took 1700 J of work to stretch a spring from its natural length of 2 m to a length of 6 m. Find the spring constant k.

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  1. 17 July, 07:11
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    212.5 N/m

    Explanation:

    Work, W = 1700 J

    y1 = 2 m

    y2 = 6 m

    y = y2 - y1 = 6 - 2 = 4 m

    Let K be the spring constant.

    Work done is given by

    W = 1/2 Ky²

    1700 = 0.5 x K x 4 x 4

    K = 212.5 N/m

    Thus, the spring constant is given by 212.5 N/m.
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