The distance between neighboring singly charged sodium and chlorine ions in crystals of table salt (NaCl) is 2.82*10^-10m.

What is the attractive electric force between the ions?

2.897*10⁻⁹ N.

Explanation:

From coulomb's law,

F = kqq'/r² ... Equation 1

Where F = attractive force between the ions, q = charge on sodium ion, q' = charge on chlorine ion, r = distance between sodium and chlorine ion, k = coulomb's constant

Given:q = 11*1.6*10⁻¹⁹ C, q' = 17*1.6*10⁻¹⁹ C, r = 2.82*10⁻¹⁰ m, k = 9*10⁹ Nm²/C²

Substitute into equation 1

F = 9*10⁹ (1.6*10⁻¹⁹) (1.6*10⁻¹⁹) / (2.82*10⁻¹⁰) ²

F = 23.04*10⁹ (2.56*10⁻³⁸) / (7.9524*10⁻²⁰)

F = (23.04*10⁻²⁹) / (7.9524*10⁻²⁰)

F = 2.897*10⁻⁹ N.