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16 March, 09:54

According to a simplified model of a mammalian heart, at each pulse approximately 20 g of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heat muscle?

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Answers (2)
  1. 16 March, 10:23
    0
    0.02 N.

    Explanation:

    Given:

    m = 20 g

    = 0.02 kg.

    vi = 0.35 m/s

    vo = 0.25 m/s

    t = 0.1 s

    Force, F = m * a

    Where,

    m = mass of the blood

    a = acceleration.

    Acceleration, a = (vi - vo) / t

    Where,

    vi = final velocity

    vo = initial velocity

    t = time.

    a = (0.35 - 0.25) / 0.1

    = 0.1/0.1

    = 1 m/s².

    F = 0.02 * 1

    = 0.02 N.
  2. 16 March, 13:01
    0
    0.02 N

    Explanation:

    Force: This can be defined as the product of mass and acceleration. The S. I unit of force is Newton.

    The formula of force is given as,

    F = ma ... Equation 1

    Where F = force exerted by the heart muscle, m = mass of the blood, a = acceleration.

    Also,

    a = (v-u) / t ... Equation 2

    Where v = final velocity, u = initial velocity, t = time.

    Given: v = 0.35 m/s, u = 0.25 m/s, t = 0.1 s

    Substitute into equation 2

    a = (0.35-0.25) / 0.1

    a = 0.1/0.1

    a = 1 m/s².

    Also given: m = 20 g = 0.02 kg.

    Substitute into equation 1

    F = 0.02 (1)

    F = 0.02 N.

    Hence the force = 0.02 N
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