Ask Question
9 October, 14:18

A ball with radius. 15 m is rolling with an angular velocity of 6.5 rad/s. (a) What linear distance will the ball roll in 5.0 seconds? The ball then slows down with a linear acceleration of - 1.2 rad/s2. (B) How fast will it be rolling rad/s after. 65 second? (C) If a piece of gum is stuck on the outer part of the ball, what is its linear speed? (4.9, 5.72,.858)

+4
Answers (1)
  1. 9 October, 17:07
    0
    (a) 4.875 m

    (b) 5.72 rad/s

    (c) 0.858 m/s

    Explanation:

    (a) Assuming constant angular speed, the angular distance the ball would have traveled after 5s at the rate of 6.5 rad/s is

    6.5 * 5 = 32.5 rad

    With radius of 0.15m, the linear distance it would have traveled is

    32.5 * 0.15 = 4.875 m

    (b) The angular velocity of the ball after 0.65s when subjected to an angular acceleration of - 1.2 rad/s is

    6.5 - 1.2*0.65 = 5.72 rad/s

    (c) The linear speed of the ball is the product of the angular speed and radius 0.15 m

    5.72 * 0.15 = 0.858 m/s
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A ball with radius. 15 m is rolling with an angular velocity of 6.5 rad/s. (a) What linear distance will the ball roll in 5.0 seconds? The ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers