A wire carrying a 32.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's field, and there is a 2.15 N force on the 3.00 cm of wire in the field. What is the average field strength (in T) between the poles of the magnet?

Question

Physics

Kaydence Wang

11 October, 17:29

A wire carrying a 32.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's field, and there is a 2.15 N force on the 3.00 cm of wire in the field. What is the average field strength (in T) between the poles of the magnet?

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Answers (1)

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Xavier Thompson · Answer 1

2.24 T

Explanation:

From Electromagnetic Field,

F = BILsin∅ ... Equation 1

Where F = Force on the wire, B = Field strength, I = current flowing in the conductor, L = length of the conductor, ∅ = The angle the conductor makes with the magnetic field.

Making B the subject of the equation,

B = F/ILsin∅ ... Equation 2

Given: F = 2.15 N, I = 32 A, L = 3.00 cm = 0.03 m, ∅ = 90° (the wire is perpendicular to the magnetic field)

Substitute into equation 2

B = 2.15 / (32*0.03*sin90°)

B = 2.15/0.96

B = 2.24 T.

Hence the Field strength = 2.24 T