Two long, straight wires are parallel and 26 cm apart.

If each wire carries a current of 57 A in the same direction, what is the magnitude of the magnetic force per meter (in N/m) exerted on each wire?

Answer: 2.49*10^-3 N/m

Explanation: The force per unit length that two wires exerts on each other is defined by the formula below

F/L = (u*i1*i2) / (2πr)

Where F/L = force per meter

u = permeability of free space = 1.256*10^-6 mkg/s^2A^2

i1 = current on first wire = 57A

i2 = current on second wire = 57 A

r = distance between both wires = 26cm = 0.26m

By substituting the parameters, we have that

Force per meter = (1.256*10^-6*57*57) / 2*3.142 * 0.26

= 4080.744*10^-6 / 1.634

= 4.080*10^-3 / 1.634

= 2.49*10^-3 N/m