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3 March, 05:02

Two long, straight wires are parallel and 26 cm apart.

If each wire carries a current of 57 A in the same direction, what is the magnitude of the magnetic force per meter (in N/m) exerted on each wire?

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  1. 3 March, 07:06
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    Answer: 2.49*10^-3 N/m

    Explanation: The force per unit length that two wires exerts on each other is defined by the formula below

    F/L = (u*i1*i2) / (2πr)

    Where F/L = force per meter

    u = permeability of free space = 1.256*10^-6 mkg/s^2A^2

    i1 = current on first wire = 57A

    i2 = current on second wire = 57 A

    r = distance between both wires = 26cm = 0.26m

    By substituting the parameters, we have that

    Force per meter = (1.256*10^-6*57*57) / 2*3.142 * 0.26

    = 4080.744*10^-6 / 1.634

    = 4.080*10^-3 / 1.634

    = 2.49*10^-3 N/m
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