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3 January, 11:29

On your wedding day, you leave for the church 25 minutes before the ceremony is to begin. The church is 11 miles away. On the way, you have to make an unanticipated stop for construction work. As a result, your average speed for the first 15 minutes is only 7 miles per hour. What average speed in miles per hour do you need for the rest of the trip to get to the church in time? Keep two decimal places.

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  1. 3 January, 15:07
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    55.50 miles/hour

    Explanation:

    time for ceremony = 25 minutes

    church miles away = 11 miles

    distance x

    velocity v

    time t

    x=v*t

    first 15 minutes:

    x = 7 miles/h * 15 min

    1 hour = 60 min

    t1 = 15 min

    t1 = 1 hour * 15 min/60 min

    t1 = 0.25 hour

    x = 7 miles/h * 0.25 h

    x = 1.75 miles

    miles left to church = 11 - 1.75 = 9.25 miles

    rest of the trip:

    x = v*t

    v=x/t

    v = 9.25 miles / (25 min-15 min) = 9.25 miles/10 min

    t2 = 10 min

    t2 = 1 hour * 10 min/60 min

    t2 = 1/6 hour

    v = 9.25 miles / (1/6) hour=9.25 * 6 miles/hour = 55.50 miles/hour
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