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25 February, 23:06

A car moves with an initial velocity of 19 m/s due north. (Part A) Find the velocity of the car after 5.6 s if its acceleration is 1.6 m/s^2 due north. (Part B) Find the velocity of the car after 5.6 s if its acceleration is 1.5 m/s2 due south.

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  1. 26 February, 00:04
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    Answer

    Assuming

    east is the positive x direction

    north is the positive y direction

    initial velocity, u = 19 j m/s

    a) acceleration, a = 1.6 j m/s^2

    Using first equation of motion

    v = u + a * t

    v = 19 + 5.6 * 1.6

    v = 28 j m/s

    the velocity of the car after 5.6 s is 28 m/s north

    b)

    acceleration, a = - 1.5 j m/s^2

    Using first equation of motion

    v = u + a * t

    v = 19 - 5.6 * 1.5

    v = 10.6 j m/s

    the velocity of the car after 5.6 s is 10.6 m/s north
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