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13 May, 20:40

A car accelerates uniformly from rest and

reaches a speed of 34.3 m/s in 10.4 s. The

diameter of a tire is 33.2 cm.

Find the number of revolutions the tire

makes during this motion, assuming no slipping.

Answer in units of rev.

+4
Answers (1)
  1. 14 May, 00:16
    0
    171 rev

    Explanation:

    Given:

    ω₀ = 0 rad/s

    ω = 34.3 m/s / (0.332 m / 2) = 207 rad/s

    t = 10.4 s

    Δθ = ½ (ω + ω₀) t

    Δθ = ½ (207 rad/s + 0 rad/s) (10.4 s)

    Δθ = 1070 rad

    Δθ = 171 rev
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