A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exerted on a 0.0500 kg bullet to accelerate it to a speed of 625 m/s in a time of 1.10 ms (milliseconds)

28409.1 N

Explanation:

Force: This can be defined as the product of mass and acceleration. The S. I unit of force is Newton (N).

From the question,

F = ma ... Equation 1

Where F = force exerted on the bullet, m = mass of the bullet, a = acceleration of the bullet.

But,

a = v/t ... Equation 2

Where v = velocity, t = time.

Substitute equation 2 into equation 1

F = m (v/t) ... Equation 3

Given: m = 0.05 kg, v = 625 m/s, t = 1.1 ms = 0.0011 s.

Substitute into equation 3

F = 0.05 (625) / 0.0011

F = 28409.1 N