Ask Question
26 April, 19:58

An overnight rainstorm has caused a major roadblock. Three massive rocks of mass m1=584 kg, m2=838 kg, and m3=322 kg have blocked a busy road. The rocks are lined up from left to right in the order m1, m2, and m3. The city calls a local contractor to use a bulldozer to clear the road. The bulldozer applies a constant force to m1 in order to slide the rocks off the road. Assuming the road is a flat, frictionless surface and the rocks are all in contact, what force,? A, must be applied to m1 to slowly accelerate the group of rocks from the road at 0.250 m/s2?

+3
Answers (1)
  1. 26 April, 23:18
    0
    Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N

    Explanation:

    Total force required = Mass x Acceleration,

    F = ma

    Here we need to consider the system as combine, total mass need to be considered.

    Total mass, a = m₁+m₂+m₃ = 584 + 838 + 322 = 1744 kg

    We need to accelerate the group of rocks from the road at 0.250 m/s²

    That is acceleration, a = 0.250 m/s²

    Force required, F = ma = 1744 x 0.25 = 436 N

    Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “An overnight rainstorm has caused a major roadblock. Three massive rocks of mass m1=584 kg, m2=838 kg, and m3=322 kg have blocked a busy ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers