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Yesterday, 11:49

In an experiment, 108 J of work was done on a closed system. During this phase of the experiment, 79 J of heat energy was added to the system. What was the total change in the internal energy of the system?

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  1. Yesterday, 12:02
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    187 J

    Explanation:

    First Law of Thermodynamics:

    ΔQ = ΔW + ΔU

    ΔQ : Heat. If it added to system then positive and if it is rejected by system then negative.

    ΔW : Work. If it done by the system then positive and if it is done on system then negative.

    ΔU : Internal Energy. If it positive then temperature of system increased and if it is negative then temperature of system decreased.

    ΔQ = 79 J

    ΔW = - 108 J

    ΔU = ?

    substituting the value in the equation:

    79 = - 108 + ΔU

    ∴ ΔU = 187 J
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