Why would Santa Ana weather conditions improve the performance of an experiment on electric charges? Conversely, why would a rainy day NOT be a good idea?
A) Santa Ana winds carry their own charges and so compensate for potential charges loss in an experiment : rainy weather does very much the opposite
B) Santa Ana winds absorbs charges than rainy weather: so random charges being compensated for
C) Santa Ana winds are very dry and so there is less charges lost into the air of lower humidity during experiment rain increases humidity as gives rise to charges lost
D) Santa Ana weather lifts the moods of experiments rainy days in general not so
E) the weather does not matter at all
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