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25 May, 17:02

A fixed mass of an ideal gas has a volume of 800 cm3 under certain conditions. The pressure (in kPa) and temperature (in K) are both doubled. What is the volume of the gas after these changes with other conditions remaining the same

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  1. 25 May, 20:03
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    800cm3

    Explanation:

    This is a general gas law question

    Which has the relationship P1V1/T1 = P2V2/T2

    P1 = P1 in kPa

    T1 = T1 in K

    V1 = 800cm3

    V2=?

    P2 = 2 * P1

    T2 = 2*T1

    The volume of gas after the changes (V2), making it as the subject of formula

    V2 = P1*V1*T2/P2*T1

    V2 = P1 * 800 * 2T1 / 2P1 * T1; dividing accordingly, we have

    V2 = 800cm3
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