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2 April, 22:26

The data and graph below were generated from a collision between Cart

1 (with mass 500 g) and Cart 2 (with mass 250 g) which occurred on a

level, frictionless track what is the total momentum

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Answers (1)
  1. 2 April, 22:46
    0
    The total momentum of the carts is p = 5000 g cm/s

    Explanation:

    Given data,

    The mass of the cart 1, m₁ = 500 g

    The mass of the cart 2, m₂ = 250 g

    Let the velocity of the cart 1 be, v₁ = 5 cm/s

    The velocity of the cart 2 be, v₂ = 10 cm/s

    According to the law of conservation of momentum, then the total momentum of the carts before and after will be the same.

    Therefore,

    p = m₁v₁ + m₂v₂

    = 500 x 5 + 250 x 10

    = 5000 g cm/s

    Hence, the total momentum of the carts is p = 5000 g cm/s
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