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10 April, 04:15

A string, stretched between two fixed posts, forms standing-wave resonances at 325 Hz and 390 Hz. What is the largest possible value of its fundamental frequency?

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  1. 10 April, 06:49
    0
    65

    Explanation:

    The resonant frequencies for a fixed string is given by the formula nv / (2L).

    Where n is the multiple.

    v is speed in m/s.

    The difference between any two resonant frequencies is given by v / (2L) = fn+1 - fn

    fundamental frequency means n=1

    i. e fn+1 - fn = 390 - 325

    = 65
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