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21 June, 15:16

A basketball is thrown straight up in the air. At its peak, it is 0.02 km high and has a velocity of 0 m/s. What is its final velocity when it hits the ground?

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  1. 21 June, 17:47
    0
    20 m/s

    Explanation:

    Given:

    Δy = 0.02 km = 20 m

    v₀ = 0 m/s

    a = 9.8 m/s²

    Find: v

    v² = v₀² + 2aΔy

    v² = (0 m/s) ² + 2 (9.8 m/s²) (20 m)

    v = 19.8 m/s

    Rounded to one significant figure, the final velocity is 20 m/s towards the ground.
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