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21 June, 16:22

100.0 g of a 4.0^°c water is heated until it's temperature is 37 °c. if the specific heat of water is 4.18 J/g°c calculate the amount of heat energy needed to cause this rise in temperature.

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  1. 21 June, 17:50
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    We can use the heat equation,

    Q = mcΔT

    Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

    Q = ?

    m = 100.0 g

    c = 4.18 J/g°c

    ΔT = (37 - 4) °C = 33 °C

    By applying the formula,

    Q = 100.0 g x 4.18 J/g °C x 33°C

    Q = 13794 J

    Hence, needed energy is 13794 J.
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