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4 January, 03:20

A person kicks a 4.0-kilogram door with a 48-newton force causing the door to accelerate at 12 meters per second squared. What is the magnitude of the force exerted by the door on the person?

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  1. 4 January, 04:16
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    -48 N

    Explanation:

    mass of door (m) = 4 kg

    acceleration of the door = 12 m/s^{2}

    force exerted by the person = 48 N

    From Newton's third law of motion, action and reaction are equal but opposite. Therefore the force exerted on the door by the person which is 48 N will be the same as the force exerted on the person by the door but opposite in its direction, and this would be - 48 N
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