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2 November, 07:42

Water flows over a section of Niagara Falls at a rate of 1.2 * 106 kg/s and falls 29 m. The acceleration of gravity is 9.8 m/s 2. How many 80 W bulbs can be lit with this power?

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  1. 2 November, 10:26
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    It can lit 4262500 Bulbs

    Explanation:

    Power: This can be defined as the ratio of energy or work done to the time taken to do the work. The S. I unit of power is Watt

    Power (P) = mgh/t ... Equation 1

    P = fall rate * height * acceleration due to gravity ... Equation 2

    Where m = mass, h = height, g = acceleration due to gravity

    Given: Fall rate = 1.2*10⁶ kg/s, g = 9.8 m/s², h = 29 m

    Substituting these values into Equation 2

    Power = 1.2*10⁶ * 9.8*29

    Power = 341.04*10⁶ W

    Power = 3.41 * 10⁸ W.

    Therefore the total power generated by Niagara fall = 3.41 * 10⁸ W.

    But, Number of bulbs it can lit = Total power/power of one bulb

    Also Given: power of one bulb = 80 W

    Therefore, Number of bulbs = 3.41*10⁸/80

    Number of bulbs = 0.042625*10⁸

    Number of bulbs = 4262500 Bulbs.

    Therefore it can lit 4262500 Bulbs
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