3-) A farm truck moves due east with a constant velocity of 9.50 m/s on a limitless, horizontal stretch of

road. A boy riding on the back of the truck throws a can of soda upward (Fig. P4.54) and catches the

projectile at the same location on the truck bed, but 16.0 m farther down the road.

(a) in the frame of reference of the truck, at what angle does the boy throw the can?.

(b) What is the initial speed of the can relative to the truck?

Question

Physics

Rubi

26 June, 06:05

3-) A farm truck moves due east with a constant velocity of 9.50 m/s on a limitless, horizontal stretch of

road. A boy riding on the back of the truck throws a can of soda upward (Fig. P4.54) and catches the

projectile at the same location on the truck bed, but 16.0 m farther down the road.

(a) in the frame of reference of the truck, at what angle does the boy throw the can?.

(b) What is the initial speed of the can relative to the truck?

+3

Answers (1)

Know the Answer?

Dante Dudley · Answer 1

given,

constant velocity = 9.50 m/s

acceleration = 0

distance = 16 m

the time of flight

s = so + ut + 1/2at²

16 = 9.50 * t

t = 1.68 s

a) to catch the can the truck he must throw it straight up, at 0° to the vertical.

b) now,

yf = Yi + UyT + 1/2at²

0 = 0 + Uy * 1.68 - 1/2 * 9.8 * 1.68²

Uy = 8.23 m/s