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26 February, 10:34

if a man jump 5 m on the Earth's surface. Then calculate the how much distance he will jump on the moon surface

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  1. 26 February, 11:52
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    30m

    Explanation:

    we know gm = 1/6 g e

    so, gm/g e = 1/6

    g e = 6 gm ... (.1)

    according to laws of motion,

    v^2 - u^2 = 2 (g e) s

    0-u^2 = 2*-g e*5

    =u^2/2g e = 5

    but from 1,

    u^2/2 (6gm) = 5

    u^2/12gm = 5

    u^2/2gm=30m
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