Ask Question
22 March, 19:26

If the force on the tympanic membrane (eardrum) increases by about 1.4 N above the force from the atmospheric pressure, the membrane can be damaged. When you go scuba diving in the ocean, below what depth (in feet) could damage to your eardrum start to occur? Considering that your eardrum is 7.4 mm in diameter. Consider the density of sea water to be 1.03*10^3 kg/m^3.

+1
Answers (1)
  1. 22 March, 21:47
    0
    10.58 ft

    Explanation:

    Force, F = 1.4 N

    Diameter of membrane = 7.4 mm

    radius of membrane, r = 7.4 / 2 = 3.7 mm = 3.7 x 10^-3 m

    Area, A = 3.14 x (3.7 x 10^-3) ^2 = 4.3 x 10^-5 m^2

    Density, d = 1.03 x 10^3 kg/m^3

    Pressure at depth, P = h x d x g

    Let h be the depth.

    Pressure = force / Area

    h x 1.03 x 10^3 x 9.8 = 1.4 / (4.3 x 10^-5)

    h = 3.225 m = 10.58 ft

    Thus, the depth of water is 10.58 ft.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If the force on the tympanic membrane (eardrum) increases by about 1.4 N above the force from the atmospheric pressure, the membrane can be ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers