Ask Question
3 April, 04:47

A 1.42-g sample of a pure compound, with formula M2SO4, was dissolved in water and treated with an excess of aqueous calcium chloride, resulting in the precipitation of all the sulfate ions as calcium sulfate. The precipitate was collected, dried, and found to weigh 1.36 g. Determine the atomic mass of M, and identify M.

+4
Answers (1)
  1. 3 April, 06:00
    0
    M2SO4 + CaCl2 = 2MCl + CaSO4

    (2M + 32 + 64) g (40 + 32 + 64) g

    (2M + 96) g of sample makes 136 g of calcium sulfate

    1.42 g will make (136 x 1.42) / (2M + 96) g

    Given,

    (136x 1.42) / (2M + 96) = 1.36

    M = 23

    It is sodium.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A 1.42-g sample of a pure compound, with formula M2SO4, was dissolved in water and treated with an excess of aqueous calcium chloride, ...” in 📙 Physics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers