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28 July, 17:25

A battery with an emf of 12 V and an internal resistance of 1 Ω is used to charge a battery with an emfof 10 V and an internal resistance of 1 Ω. The current in the circuit is : A) 2 A B) 1 A C) 4A D) 11A E) 22 A

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  1. 28 July, 19:43
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    Option B

    Explanation:

    The net emf in the circuit

    E = 12 - 10 = 2 V

    Total effective resistance,

    r = 1 + 1 = 2 ohm

    By using Ohm's law

    E = I * R

    I = 2 / 2 = 1 A
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