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23 November, 05:49

A cable applies a vertical force to a crate with a mass of 70.0 kg. It first lifts the crate to a height of 12.0 m above the floor, and then lowers it back to the floor. What is the total work done by the force?

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  1. 23 November, 08:03
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    The total work done is zero.

    Explanation:

    Given;

    mass of the crate, m = 70.0 kg

    height above ground through which the crate is lifted, h = 12.0 m

    The only work associated in lifting and lowering this crate is gravitational potential energy.

    Potential Energy during lifting = - mgh

    = - 70 x 9.8 x 12

    = - 8232 J

    Potential Energy during lowering = mgh

    = 70 x 9.8 x 12

    = 8232 J

    Total total work done by the force = - 8232 J + 8232 J = 0

    Therefore, the total work done is zero.
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