Light from a laser of wavelength λ1 shines normally on a pair of narrow slits separated by distance D. This results in a difference in angle between the central and first intensity maxima of 0.02 radians. A second laser of wavelength λ2=2λ1 then shines on the same slit system. The new angular difference between the central first intensity maxima is closest to:

Question

Physics

Mad Max

29 August, 01:50

Light from a laser of wavelength λ1 shines normally on a pair of narrow slits separated by distance D. This results in a difference in angle between the central and first intensity maxima of 0.02 radians. A second laser of wavelength λ2=2λ1 then shines on the same slit system. The new angular difference between the central first intensity maxima is closest to:

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Benton · Answer 1

The angular position of first intensity maxima is given by the expression

= λ / d where λ is wave length of light and d is slit separation

putting the values given in the problem.,

.02 = λ₁ / D

Now wavelength has been increased to 2λ₁

angular separation of first maxima

= 2λ₁ / D

= 2 x. 02

=.04 radians.