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Today, 00:19

A sample of blood is placed in a centrifuge of radius 12.0 cm. The mass of a red blood cell is 3.0 ✕ 10^-16 kg, and the magnitude of the force acting on it as it settles out of the plasma is 4.0 ✕ 10^-11 N. At how many revolutions per second should the centrifuge be operated?

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Answers (2)
  1. Today, 00:53
    0
    167.85 rev / s

    Explanation:

    At 167.85 rev / s should the centrifuge be operated.

    f = w / 2 π = 1054.1 / (2 x 3.14)
  2. Today, 03:15
    0
    167.85 rev / s

    Explanation:

    r = 12 cm = 0.12 m, m = 3 x 10^-16 kg, F = 4 x 10^-11 N

    F = m r w^2

    where, w is the angular velocity.

    4 x 10^-11 = 3 x 10^-16 x 0.12 x w^2

    w = 1054.1 rad / s

    w = 2 π f

    f = w / 2 π = 1054.1 / (2 x 3.14) = 167.85 rev / s
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