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28 November, 19:06

What is the work done on a 30 kg object if a force of 15 N is applied for 5 seconds?

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  1. 28 November, 22:12
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    Work done is 93.75J

    Explanation:

    Given mass, m = 30kg; Time = 5 seconds; force = 15N; u = 0

    Acceleration, a = F/m ⇒ 15/30

    ⇒ 0.5ms

    Displacement, s = ut+1/2at²

    ⇒ 0 + 1/2 (0.5*5*5)

    ⇒ 0 + 1/2 (0.5*25)

    ⇒ 0 + 1/2 (12.5)

    ⇒ 0 + 6.25

    ⇒ 6.25m

    work done = Fs=15*6.25 = 93.75 J
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