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4 December, 10:45

Basking in the sun, a 1.10 kg lizard lies on a flat rock tilted at an angle of 15.0° with respect to the horizontal. What is the magnitude of the normal force exerted by the rock on the lizard? a. 10.5 N c. 10.4 N b. 2.8 N d. - 10.5 N

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  1. 4 December, 13:26
    0
    10.4 N

    Given

    m = 1.10 kg

    θ = 15.0°

    g = 9.81 m/s2

    Solution

    Fnet, y = ΣF y = Fn - Fg, y = 0

    Fn = Fg, y = Fg

    cosθ = mgcosθ

    Fn = (1.10 kg) (9.81 m/s2

    ) (cos15.0°) = 10.4 N
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