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16 March, 17:16

A bullet B of mass mB traveling with a speed v0 = 1400 m/s ricochets off a fixed steel plate A of mass mA. Let mA ≫ mB so that it can be assumed that mBmA→0. If the incidence angle of the bullet is θ = 15° and the COR of the impact is e = 0.5, determine the rebound angle ϕ, as well as the bullet's rebound speed.

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  1. 16 March, 20:47
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    Rebounce angle is 345°

    Rebounce speed is 989.95m/s

    Explanation:

    Calculate the x component of the velocity of the bullet before impact by using the following relation:

    Vbx = Vb Cos thetha

    Here, is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet. = theta = 15°

    Substituting

    Vbx = Cos15 * 1400 = 1352.30m/s

    Calculate the y component using the relation:

    Vby = Vo Sin theta

    Vby = sin 15° * 1400

    Vby = 362.35m/s

    The rebounce angle = 360 - incidence angle

    Rebounce angle = (360 - 15) ° = 345°

    The rebound speed V' = Vby - Vbx

    V' = (1352.30 - 362.35) m/s

    V' = 989.95 m/s
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