A cessna 150 airplane has a takeoff speed of 28 m/s. determine the minimum length of the runway which would be required for the plane to take off if it averages an acceleration of 1.9 m/s/s.

Given: Takeoff Speed (u) = 28 m/s

Final velocity (v) = 0.0 m/s

Acceleration (a) = 1.9 m/s²

To calculate: The minimum length of runway (s) = ?

Solution: Apply 3rd kinematic equation of motion

v² = u² - 2as

Or, s = (u² - v²) / 2 a

Or, s = (28² - 0²) / 2 * 1.9 m

Or, s = 206.3 m

Hence, the required minimum length of the runway will be 206.3 m