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6 August, 00:28

A mass M is suspended from a spring and oscillates with a period of 0.940 s. Each complete oscillation results in an amplitude reduction of a factor of 0.96 due to a small velocity dependent frictional effect. Calculate the time it takes for the total energy of the oscillator to decrease to 0.50 of its initial value.

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  1. 6 August, 03:34
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    The time, t = 7.99seconds

    Explanation:

    Total energy of SHM system is:

    E = ½kA²

    0.50E = 0.50 (½kAo²) = ½kA²

    A = Ao/√2 = 0.707Ao

    The amplitude after each oscillation is given by:

    A (n) = Ao (0.96) ^n

    Solve for n by setting this equal to half-energy amplitude:

    Ao (0.96) ^n = Ao/√2

    ln (Ao (0.96) ^n) = ln (Ao/√2)

    ln (Ao) + n*ln (0.96) = ln (Ao) - ln (√2)

    n = - ln (√2) / ln (0.96)

    n = 8.5

    Find time from n & period T:

    Period, T = 0.940seconds

    t = 8.5 * 0.940

    t = nT = 7.99s
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