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23 May, 06:57

A box with a total surface area of 1.88 m^2

and

a wall thickness of 2.44 cm is made of an insulating material. A 14.1 W electric heater

inside the box maintains the inside temperature at 18.6

◦C above the outside temperature.

Find the thermal conductivity of the insulating material.

Answer in units of W/m ·

◦ C.

+3
Answers (1)
  1. 23 May, 09:05
    0
    Answer:9.8x10^ (-3) w/m°C

    Explanation:

    Quantity of heat (Q) = 14.1w

    Distance (d) = 2.44cm=2.44/100=0.0244m

    Area (a) = 1.88m^2

    Temperature change (t) = 18.6°C

    thermal conductivity (k) = ?

    K = (Qxd) ➗ (a x t)

    K = (14.1x0.0244) ➗ (1.88x18.6)

    K=0.34404 ➗ 34.968

    K=9.8x10^ (-3) w/m°C
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