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23 May, 07:04

A body of mass 2 kg at O has an initial velocity of 3m/s along OE and it is subjected to a force of 4N perpendicular to OE the distance covered in 4 seconds?

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  1. 23 May, 07:50
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    Perpendicular acceleration:

    F = ma

    a = 4 / 2 = 2 m/s²

    Perpendicular distance:

    s = ut + 1/2 at²

    s = 0 x 4 + 1/2 x 2 x 4²

    s = 16 m

    Horizontal distance:

    s = ut

    = 3 x 4

    = 12 m

    Total distance = √ (12² + 16²)

    = 20 m.
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