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12 May, 15:32

Assume that room pressure is 97.3 kPa. Suppose you started with 15 mL of air in the syringe at room pressure. If the air is compressed to 3.0 mL, what will the new pressure be?

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  1. 12 May, 17:37
    0
    room pressure p1 = 97.3 kPa

    initial volume of air v1 = 15 mL

    the air was compressed to a new volume of 3.0mL

    using Boyle's law

    p1v1 = p2v2

    97300 * 15 mL = p2 * 3.0 mL

    p2 = 1459500 / 3 = 486500 Pa = 486.5 KPa
  2. 12 May, 19:24
    0
    Answer: the new pressure is 486.5 kpa

    Explanation:

    We would apply Boyles law which states that the volume of a gas is inversely proportional to its pressure when the temperature of the gas is held constant.

    It is expressed as

    P1V1 = P2V2

    Where

    P1 represents initial pressure of the gas.

    V1 = initial volume of the gas

    P2 = final pressure of the gas

    V2 = final volume of the gas

    The gas is the air that is being compressed by the syringe. From the information given,

    P1 = 97.3 kPa.

    V1 = 15 mL

    V2 = 3.0 mL

    P2 = ?

    Therefore,

    97.3 * 15 = 3 * P2

    1459.5 = 3P2

    P2 = 1459.5/3

    P2 = 486.5 kpa
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