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10 April, 23:42

In a football game, the running back takes a handoff and begins running toward midfield at 3.21 yards/s. As he moves through his linemen, he accelerates at a rate of 1.71 yards/s^2 to a velocity of 7.54 yards/s before he is tackled. How far did he run after he got the ball?

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  1. 11 April, 02:29
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    Given Information:

    Initial speed = u = 3.21 yards/s

    Acceleration = α = 1.71 yards/s²

    Final speed = v = 7.54 yards/s

    Required Information:

    Distance = s = ?

    Answer:

    Distance = s = 13.61

    Explanation:

    We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.

    We know from the equations of motion,

    v² = u² + 2αs

    Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.

    Re-arranging the above equation for distance yields,

    2αs = v² - u²

    s = (v² - u²) / 2α

    s = (7.54² - 3.21²) / 2*1.71

    s = 46.55/3.42

    s = 13.61 yards

    Therefore, the runner traveled a distance of 13.61 yards before being tackled.
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