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25 January, 21:56

An unknown force is applied to a 12 kg. The force acts at an angle of 30 degrees above the horizontal. Determine the force acting if the force acts for a horizontal displacement of 22 meters and increases the 12 kg mass's speed from 11 m/s to 26 m/s

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  1. 26 January, 01:38
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    Time it take to displace to 22 m:

    D = 0.5 (Vi-Vf) t

    22m = 0.5 (11 + 26) t

    t = 1.189 s

    Acceleration

    22m = vt + 0.5at^2

    a = 12.616 m/s^2

    F = ma

    F sin 30 = 12 kg x 12.616 m/s^2

    F = 302.805 N
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