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23 January, 13:00

A certain reaction has an activation energy of 67.72 kJ/mol. At what Kelvin temperature will the reaction proceed 4.00 times faster than it did at 353 K?

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  1. 23 January, 16:29
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    T1 = 363 K

    T2 = ?

    R = 8.3145 J/mol K

    K1 = 1

    K2 = 4

    Ea = 67.72 x 1000 = 67720 J/mol

    T2 = 1 / (1/363) - (8.3145 / 67720) x ln (4 / 1)

    T2 = 1 / 0.00258461502

    T2 = 386.90 K
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