As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?

A) 0.827

B) 0.944

C) 1.21

D) 1.06

Question

Physics

Wendy Mckee

18 March, 14:19

As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?

A) 0.827

B) 0.944

C) 1.21

D) 1.06

+1

Answers (1)

Know the Answer?

Elliana Wilcox · Answer 1

The equation for the index of refraction is n = sin (theta1) / sin (theta2) where theta1 is the refracted angle and theta2 is the angle in a medium. Plugging in the values for the index of refraction, n = sin (32) / sin (26) we get 1.21. the answer is letter C. The index of refraction is always greater than 1.

As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?A) 0.827B) 0.944C) 1.21D) 1.06

As light shines from air to another medium, i = 26.0 º. The light bends toward the normal and refracts at 32.0 º. What is the index of refraction?

A) 0.827

B) 0.944

C) 1.21

D) 1.06