A vw beetle goes from 0 to 60 mi/h with an acceleration of 2.35 m/s^2.

a. how much time does ti take for the beetle to reach 60 mi/h?

b. a top - fuel dragster can go from 0 to 60 mi/h in 0.600 seconds. find the acceleration (m/s^2) of the dragster.

Part a.

u = 0, the initial velocity

v = 60 mi/h, the final velocity

a = 2.35 m/s², the acceleration.

Note that

1 m = 1609.34 m.

Therefore

v = (60 mi/h) * (1609.34 m/mi) * (1/3600 h/s) = 26.822 m/s

Use the formula

v = u + at

(26.822 m/s) = (2.35 m/s²) * (t s)

t = 26.822/2.35 = 11.4 s

Answer: 11.4 s

Part b.

We already determined that v = 60 mi/h = 26.822 m/s.

t = 0.6 s

Therefore

(26.822 m/s) = (a m/s²) * (0.6 s)

a = 26.822/0.6 = 44.7 m/s²

Answer: 44.7 m/s²