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15 October, 19:38

The input work done on a machine is 9.63 * 103 joules, and the output work is 3.0 * 103 joules. What is the percentage efficiency of the machine?

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  1. 15 October, 22:40
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    Input work = 9.63*10³ J.

    Output work = 3.0*10³ J

    By definition,

    Efficiency = (Output work) / (Input work)

    = (3.0*10³) / (9.63*10³)

    = 0.31 = 31%

    Answer: 31%
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