An object moves with constant acceleration 4.00 m/s^2 and over a time interval reaches a final velocity of 12.0 m/s.

a) If its initial velocity is - 6.00 m/s, what is its displacement during the time interval.

b) What is the total distance it travels during the time interval in part b?

A) We can use the equation of motion:

2as = v² - u²

s = (12² - (-6) ²) / 2 x 4

s = 13.5 m

b) We calculate the time over which this displacement occurred using:

v = u + at

t = (12 - - 6) / 4

t = 4.5 seconds

Assuming the average speed equal to:

(12 + 6) / 2 = 9 m/s

average speed = total distance/total time

total distance = 9 x 4.5

= 40.5 m